Yet Another Stoichiometry Lab, Only This Time It's Dry

Technically called Stoichiometry of a Double Replacement Reaction, but anyway. Since this is too dangerous/toxic/nasty to do in real life, we were given a piece of paper, and told to do this has a dry lab. So:

Procedure:

1. Clean and dry two beakers
2. Record the number of you chemical: Lab #5
3. Find the mass of lead(II) nitrate: 1.03 grams
4. Find the mass of potassium iodide: 1.33 grams
5. Add about 50mL of DI water to each beaker
6. Stir the beakers until both chemicals have dissolved
7. Combine the contents of both beakers into one beaker
8. Wash any remaining solution into the one beaker
9. Stir the solution
10. Measure the mass of filter paper: 1.39 grams
11. Filter out the precipitate into the filter paper
12. Wash any remaining precipitate into the filter paper 
13. Allow the precipitate and filter paper to dry overnight
14. Find the mass of the precipitate: .95 grams

The balanced equation for the chemical reaction is: 2KI + Pb(NO3)2 -> 2KNO3 + PbI2

The limiting reagent for this experiment was: Lead (II) Nitrate

Theoretically, there should be: 1.43 grams of lead(II) iodide formed from the experiment

In reality, there was actually: .95 grams of lead(II) iodide formed from the experiment

The percent yield of lead(II) from the experiment was: 66%

Here is my work to figure out all of the lovely answers. It's just proof, don't expect me to explain this all again.